Choose the point which is a solution to the system of inequalities: 4x + 3y > 12 x – y < –2
If they give you a list of options, just check each one. Look at the point, figure out what x and y are. Plug x and and y into each inequality to see if they give you a true statement.
what are your points?
(2, 1) (–4, 9) (–5, –6) (3, 7)
Here's an example point: (5,10) x = 5 y =10 Check the first inequality. 4(5) + 3(10) >12 ? 20 + 30 > 12 50>12 so yes Check the second inequality (5) - (10) < -2 ? -5 < -2, so yes.
Let us see your attempt for each point. We will help with any questions that come up.
hold on .. ima write them down my paper first
Kev, let her try it on her own.
so the answer is... ok I'll wait
for the (-4,9) 4x + 3y >12 x - y <-2 4(-4) + 3(9) > 12 -16 + 27 > 12 11 > 12 -4 - 9 < -2 13 < - 2 i dont think that -4, 9 is right tho O.o .. is it?
The answer is 3,7 4(3)+3(7)=33 true 3-7<-2
Wow, Kev. You're jumping the gun.
ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
do you see the answer
the first three fail and are not true
i see it now thank you Kev thank you thank you and thanks smooth math guy a lot ....
just plug each one in turn and get the ansewr compare that with the equality and its either true or false
if false move on
Tati, you did that point correctly. Plugging those points in gives you 11 > 12 and -13 < -2 So, there would be one correct inequality and one incorrect. They both have to be true for the point to be a solution.
ohhh i see that
Do the same with the other points. If the point makes both inequalities true, then it is a solution =D
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