Question

Please help I don't understand this one at all.
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (– 3, – 25),
and x intercepts at x = -8 and x = 2.

y = x2 + 6x -_____

Answer 1

graph

x2 + 6x

see where vertex is at use google or your graph calc

Answer 2

x^2 + 6*x

Answer 3

the vertex is -3,-9

you dont have to do nothing to the -3 but you do have to shift it down till it reaches -25

so -25=x+(-9) x=-16

so

y = x2 + 6x -_____

y = x^2 + 6x -16 :)

Answer 4

\[y=(x+8)(x-2)\]
\[y=x^2+6x-16\] and you can check that if you replace \(x\) by -3 you get
\[(-3)^2+6\times -3-16=9-18-16=-9-16=-25\]

Answer 5

dude that is too much

y = x2 + 6x you are given

it ask for y = x2 + 6x - c

All you have to do is shift it down :)

Answer 6

Thank you both!