Which is a set of roots for the quadratic equation x^2+10x-24=0
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OpenStudy (anonymous):
can you factor the left side?
OpenStudy (anonymous):
i think so
OpenStudy (anonymous):
so what two numbers multiply to -24 and add to 10?
OpenStudy (anonymous):
-24 = ??? * ????
10 = ??? + ????
OpenStudy (anonymous):
-12*2=-24
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OpenStudy (anonymous):
5+5=10
OpenStudy (anonymous):
12 * -2 = -24
12 + -2 = 10
they have to be the same numbers for both...
OpenStudy (anonymous):
6 and 4
OpenStudy (anonymous):
it takes practice but that's the two numbers you're looking for 12 and -2.
OpenStudy (anonymous):
ohh thanks :D
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OpenStudy (anonymous):
so the equation: x^2+10x-24=0 can be factored as
x^2+10x-24=0
(x+12)(x-2) = 0
now it's easy to solve...
x+12 = 0 and x-2=0
solve these two to get the solution for your original question.... :)
OpenStudy (anonymous):
you ok from here? what's the solution set?
OpenStudy (anonymous):
{12,-2}
OpenStudy (anonymous):
^was the answer
OpenStudy (anonymous):
no... it's {-12, 2}
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OpenStudy (anonymous):
ohh..
OpenStudy (anonymous):
you have to solve that last two equations:
x+12=0 and x-2=0
OpenStudy (anonymous):
that's why it's -12 and 2 and not the other way around... :)