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how to integrate \[\int \frac{2+v}{1+v^2}\]
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Separate into 2 fractions: \[\frac{2}{1+v^2}+\frac{v}{1+v^2}\] then integrate separately.
seperate it into 2 integ question first is intg (2/(1+v2)) and the other is 1/2 intg(2v/(1+v2)) and thus the ans is 2tan-1 v +1/2 ln|1+v2| + c
@blockcolder how do you integrate 2/(1+v)^2
Don't you mean 2/(1+v^2)?
yeah
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Here's a rule for safe-keeping: \[\int \frac{1}{1+x^2} dx=\tan^{-1}x+C\]
oh..yeah of course *facepalm*
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