Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.

38 and 40
40 and 42
42 and 44

Thank you!

Question

Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.

38 and 40
40 and 42
42 and 44

Thank you!

parthkohli · Answer

Hmm I see.
You may check from the options.

parthkohli · Answer

$\Large \color{MidnightBlue}{\Rightarrow {1 \over 2}x - {2 \over 5}(x - 1) = 5 }$

anonymous · Answer

38 nd 40

parthkohli · Answer

Nope. Not correct.

parthkohli · Answer

To get a whole number 5, the smaller number must be divisible by 5, or else you get a fraction/decimal

parthkohli · Answer

Basically the bigger one must be divisible by 2 and the smaller one by 5.

anonymous · Answer

It's not 38 and 40 parth?

parthkohli · Answer

Nope. 38 is not divisible by 5.

anonymous · Answer

So I see. Thank you.

parthkohli · Answer

One of these options have the smaller number divisible by 5.

parthkohli · Answer

If my answer confused you, then solve the equation I gave, or check it by multiplying the bigger one by 1/2 and smaller one by 2/5 then subtracting them.

anonymous · Answer

Thank you ParthKohli, for all the help.

parthkohli · Answer

=)

anonymous · Answer

40 and 42 will be the correct answer 
the equation will be$$x/2-2(x-2)/5=5$$

parthkohli · Answer

Oh no yeah you're correct

parthkohli · Answer

Even numbers.

parthkohli · Answer

But I was correct about divisible by 5 part

anonymous · Answer

Thank you both<3