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Mathematics 17 Online
OpenStudy (anonymous):

0=x^3+2x-3, solve for x. this looks impossible

OpenStudy (anonymous):

3=x^3+2x

OpenStudy (anonymous):

so is this just guess and check? lol

OpenStudy (cwrw238):

you can get approximate roots by drawing a graph then more accurate ones by method of trial and improvement

OpenStudy (anonymous):

so cwrw, its just guess and check?

OpenStudy (cwrw238):

actually by observation one root is x=1

OpenStudy (anonymous):

yeah i know the answer is 1, but i want to know the method

OpenStudy (anonymous):

sorry

OpenStudy (cwrw238):

as i say drawing a graph would help - there may be other roots not just 1

OpenStudy (anonymous):

so is this this the way to solve it for equations like: ax^3+bx+c?

OpenStudy (anonymous):

=0?

OpenStudy (cwrw238):

its one way - there may be others trial and improvement is a valid way but can be tedious if you know from the graph that root lies between 1 and 2 say you try 2.1, 2.2 etc until you get f(x) passing through 0

OpenStudy (cwrw238):

SMISHRA - r u from eastern europe?

OpenStudy (anonymous):

Do you know Cardan's Solution.

OpenStudy (cwrw238):

no - never heard of it

OpenStudy (cwrw238):

i drew a rough graph - theres only 1 solution (1)

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