0=x^3+2x-3, solve for x. this looks impossible
3=x^3+2x
so is this just guess and check? lol
you can get approximate roots by drawing a graph then more accurate ones by method of trial and improvement
so cwrw, its just guess and check?
actually by observation one root is x=1
yeah i know the answer is 1, but i want to know the method
sorry
as i say drawing a graph would help - there may be other roots not just 1
so is this this the way to solve it for equations like: ax^3+bx+c?
=0?
its one way - there may be others trial and improvement is a valid way but can be tedious if you know from the graph that root lies between 1 and 2 say you try 2.1, 2.2 etc until you get f(x) passing through 0
SMISHRA - r u from eastern europe?
Do you know Cardan's Solution.
no - never heard of it
i drew a rough graph - theres only 1 solution (1)
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