Question

Help & showing working out thanks, picture attached.

Answer 1

Suppose the gradient of a line is m. the gradient of the line perpendicular to this will be -1/m.

Answer 2

yep m1 x m2 = -1

Answer 3

for Q9 I figured out m1=1/20 and so m2=-20 but I do not know the equation that is perpendicular to the original line.

Answer 4

There are many lines that are perpendicular to the given line. You only have to give one. So just make an equation that has slope -20 and an arbitrary y intercept. Perhpaps y = -20x

Answer 5

kk, well I did get that question wrong and the teacher wrote y=-20x + c so ur right and it means that c also known as the y-intercept can be any value, I believe.

Answer 6

That is correct.

Answer 7

any clues on how to do Q12?

Answer 8

The slope of the two lines can be found by using m = -a/b. So the slope of the first line is 4/3 and the slope of the second line is 4/l

Answer 9

So, is they are perpendicular, then
\[\frac{4}{3}(\frac{4}{L})=-1\]
And:
\[-3L=16, L=\frac{-16}{3}\]

Answer 10

So now replace x and y with the given coordinates and find p

Answer 11

p=80/3 I believe?

Answer 12

\[4(4)-(\frac{-16}{3})(2)=p=\frac{80}{3}\]

Answer 13

I concur

Answer 14

yes, at least I got that right lol. u made it seem so simple.

Answer 15

One small step at a time.

Answer 16

yep, thanks Mertsj!

Answer 17

wait, I have some more questions, can u still help me?

Answer 18

And I don't know why you missed the first one because it says to find the equation of A line that is perpendicular to the given line. The answer y=-20x + c is the equation of ALL lines perpendicular to the given line.

Answer 19

yes, wen ur in a test situation it's different and besides I'm stupid so that explains why I missed it.

Answer 20

Just remember: for a polynomial, you can't have fractional exponents for the variable, you can't have negative exponents for the variable, and you can't have a variable in the denominator. So which one is it?

Answer 21

B and so a square root, cube or greater will always have a fraction exponent right?

Answer 22

r u doing Q12,b and Q13?

Answer 23

That function has no abolute maximum or minimum since it goes on and on forever.