Question

how to integrate \[\large \int \frac{(4v^2 + 8v - 1)dv}{4v^3 + 4v^2 + v + 1}\]

Answer 1

i just need a hint :D

Answer 2

1+1 = 2

Answer 3

hmm makes sense

Answer 4

thanks

Answer 5

Sure it does. ;)

Answer 6

Have you tried partial fraction decomposition?

Answer 7

Try factoring the denominator

Answer 8

exactly...how??

Answer 9

i dont get your point...

Answer 10

=_=

Answer 11

sorry.. i've been on medication..@!!!!

Answer 12

lol

Answer 13

Start with \[4v^3+4v^2+v+1\]\[4v^2(v+1)+(v+1)\]\[(4v^2+1)(v+1)\]
Then do a separation of variables.

Answer 14

makes sense

Answer 15

Oops, meant partial fractions.

Answer 16

is it a = -40/3
b =8
c = 13/3

Answer 17

These are the equations that I got, and I don't think they yield the same solutions. I may have done a step incorrectly though...

Answer 18

i see where i went wrong thanks!

Answer 19

Sure thing :)

Answer 20

a = 8
b = 0
c = -1

Answer 21

Yep, that's what I got, too.

Answer 22

yay