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Solve: log (2x + 1) - log x = log 4
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\[\ \log (2x + 1) - \log x = \log 4\] We know that \[\log a-\log b=\log \frac ab\] Applying this here, we get \[\log \frac{2x+1} {x}=\log 4\] Now we take anti log both sides \[\frac{2x+1} {x}= 4\] Can you solve for x now?
Can you keep going just in case. o; I'm super paranoid. Lool.
Give it a try, if you get stuck I'll help you
I got 1/2
Good, that's right:D
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Tysm C:
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