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(e^2e^3/2)^4/3
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\[(e ^{2}e ^{3/2})^{4/3}\]
another thing... \[(a^x a^y) = a^{x+y}\]
therefore \[(a^xa^y)^z = a^{z(x+y)}\]
got what that means?
Yes, its just like the other one just longer :).
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yes...indeed
so you can do it from here?
\[(e ^{2}e ^{3/2})^{4/3}\] \[e ^{2/1}\times ^{4/3})(e ^{3/2}\times ^{4/3})\] Do I multiply those?
yeah
\[e ^{14/3}\]It says the answer is
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YES!!!
@lgbasallote
yes?
Got it! :) thanks
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