The probability that a blue eyed person is left handed is 1/7. The probability that left handed person is blue eyed is 1/3. The probability that a person has neither of these attributes is 4/5. What is the probability that a person has both these attributes?
1/21
the answer is 1/45 though
woah! how? i thought you just multiply the demoninators...
im sorry.. :(
somewhere i must use conditional probability but what is given in P(L|B)
ohh, never used conditional probability..
its ok :) like, is the question saying that, given the person is blue eyed...the prob that the person is left handed is 1/7?
just re-reading, how does that make sense? their both blue eyed and left handed..
i am very confused...
The probability that a blue eyed person is left handed is 1/7 For example, we can assign 6 blue eyed to "only blue eyed" and 1 in the intersection with left handed. The probability that left handed person is blue eyed is 1/3. We could, for example, assign 2 people to only left-handed and 1 to both blue eyed and left-handed There are a total of 9 people in these categories Probability of neither of these attributes is 4/5. So these 9 people represent 1/5 of the total population, which must be 5*9= 45. 4/5 or 36 of the population are outside the 2 circles. |dw:1338733623413:dw| Looking at the picture, we see only 1 out of 45 fits the category both blue eyed and left-handed.
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