Mathematics
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OpenStudy (anonymous):
Find the distance CB for the points c(8, -6) and B(6, 7).
A) distance = √198
B) distance = √197
C) distance = √172
D) distance = √173
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OpenStudy (mertsj):
So now that Parth posted the distance formula for you, why don't you use it?
OpenStudy (mertsj):
Subtract the x coordinates of the points. Subtract the y coordinates of the points. What do you get?
OpenStudy (anonymous):
I've never done this stuff so idk.....
OpenStudy (mertsj):
In the ordered pair, (8,6) which is the x?
OpenStudy (anonymous):
8?
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OpenStudy (mertsj):
In the ordered pair (6,7) which is the x?
OpenStudy (anonymous):
6
OpenStudy (mertsj):
Subtract those two numbers. What do you get?
OpenStudy (anonymous):
2
OpenStudy (mertsj):
Remember that number. We'll come back to it.
In the ordered pair (8,-6) what is the y?
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OpenStudy (anonymous):
-6
OpenStudy (mertsj):
In the ordered pair (6,7) what is the y?
OpenStudy (anonymous):
7
OpenStudy (mertsj):
Subtract those two numbers. What do you get?
OpenStudy (anonymous):
Am I doing -6 - 7 or 7 - 6?
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OpenStudy (mertsj):
Doesn't matter if you do -6-7 or 7-(-6)
OpenStudy (mertsj):
Because you are going to square it anyway.
OpenStudy (anonymous):
-6 - 7 = -13
7 - -6 = 1
OpenStudy (mertsj):
7-(-6)=7+6=13
OpenStudy (mertsj):
What was the other number you rememberes?
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OpenStudy (mertsj):
remembered?
OpenStudy (anonymous):
8 - 6 = 2
OpenStudy (mertsj):
Square the 2 and square the 13. What do you get?
OpenStudy (mertsj):
\[2^2= ???\]
\[13^2=???\]
OpenStudy (anonymous):
2² = 4 & 13²= 169
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OpenStudy (mertsj):
Add them together. What do you get?
OpenStudy (anonymous):
do I add those together? Which make 173?
OpenStudy (mertsj):
Take the square root and that is your distance.
OpenStudy (anonymous):
So it's 173?
OpenStudy (mertsj):
That's why I drew you the picture in the question you closed. It's just a special case of the Pythagorean Theorem.
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OpenStudy (mertsj):
Did you take the square root?
OpenStudy (anonymous):
Umm, how do you take the square root?
OpenStudy (mertsj):
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