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If sin(Θ)=x^2, what is sin(2Θ) in terms of x?
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do you know how to express sin(2a) in terms of sin(a) and cos(a)?
um, sin(2a)=2sin(a)cos(a), right?
perfect - now you just need to express cos(a) in terms of sin(a). do you know how to do that?
Is it cos(a)=sin(a+π/2)? cuz that's where i'm stuck.
no - use the following identity:\[\sin^2(a)+\cos^2(a)=1\]
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the rest should be simple
Oh...OK. So it is 2x^2 sqrt(1-x^4)
that looks right to me
Thanks for your help!
yw :)
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note in some cases you will need \[-2x^2\sqrt{1-x^4}\]
yes indeed - @Zarkon spotted something we both failed to spot:\[\cos(a)=\pm\sqrt{1-\sin^2(a)}\]
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