Harry folds his origami paper along the dotted lines shown below so that the triangular flaps overlap exactly on the square.

If the dimensions of the origami paper are decreased by , what will be the new area of the paper?
8 square inches
16 square inches
32 square inches
48 square inches

Question

Harry folds his origami paper along the dotted lines shown below so that the triangular flaps overlap exactly on the square. 



If the dimensions of the origami paper are decreased by , what will be the new area of the paper?  
8 square inches
16 square inches
32 square inches
48 square inches

anonymous · Answer

attachment

anonymous · Answer

The dimensions are being decreased by 1/2

anonymous · Answer

@KingGeorge Do you know anyone that could help with this?

kinggeorge · Answer

Well, the new area of the paper should just be the area of that square. And the side length's of the square are $4\sqrt2$. What's the area of a square with a side length of $4\sqrt2$?

anonymous · Answer

$$8\sqrt{2}$$

kinggeorge · Answer

Not quite. You're multiplying the side length by two, when you need to multiply it by itself. $$4\sqrt2\cdot4\sqrt2=(4\cdot4)\cdot(\sqrt2\cdot\sqrt2)=16\cdot2=32$$So the area should be 32 square inches.