Question

Simplify Cosx^2*Cscx^2-Cscx^2

Answer 1

Which one is your question, (i) or (ii)?
\[(i) cosx^2\times cscx^2-cscx^2\]\[(ii) cos^2x\times csc^2x-csc^2x\]

Answer 2

uhmm. actually it is theta... i put x to make it simpler to write. It is exactly Cos^2(theta)*csc^2(theta)-csc^2(theta)

Answer 3

so i guess the 1st

Answer 4

\[cos^2\theta\times csc^2\theta-csc^2\theta\] This?

Answer 5

yes

Answer 6

any ideas?

Answer 7

lol Then, it's the second :)
\[cos^2\theta\times csc^2\theta-csc^2\theta\]\[ = csc^2\theta (cos^2\theta -1)\]\[=csc^2\theta [-(1-cos^2\theta )]\]\[=csc^2\theta (-sin^2\theta )\]
One step left (or 2..), can you work it out?

Answer 8

you got cos^2-1 from finding a GCF?

Answer 9

kinda.... Actually, by factorization

Answer 10

Can you please show me it since its all ^2?

Answer 11

Hmm... actually, I've shown you... but I can explain little more...
Consider \[cos^2\theta\times csc^2\theta-csc^2\theta\]
\(csc^2\theta\)is the common factor of the 2 terms, got it so far?

Answer 12

yse i think so

Answer 13

so wouldnt it be csc^2(1-1)?

Answer 14

if you just did the common factor

Answer 15

Nope :|
Take OUT the common factor and group the rest of the terms...