Question

(2x+5)(x-4)

Answer 1

I get stuck on the "foil"

Answer 2

(2x+5)(x-4)=0
2x + 5 = 0 x - 4 = 0
2x = -5 x = 4
x = -5/2

Answer 3

FOIL

multiply the First terms
multiply the Outside terms
multiply the Inside terms
multiply the Last terms

first terms are 2x and x
outside terms are 2x and -4
inside terms are 5 and x
last terms are 5 and -4

Answer 4

So far I have
2x^2-2x+5x+1
2x^2+3x+1
2x^2+3x=-1
2x^2=-1/3
this is where i get stuck. I'm sure I'm doing something worng

Answer 5

would it just be 2x^2-3x-20?

Answer 6

yep.
Here it is step by step
(2x+5)(x-4)
2x*x + 2x*(-4) + 5*x + 5*(-4)
2x^2 - 8x + 5x - 20
2x^2 - 3x - 20

Answer 7

or are you trying to solve for x?
In that case you can solve each term like
2x+5 = 0 => x = -5/2
and
x-4 = 0 => x = 4,

so your solution is x = -5/2 and 4

Answer 8

it just says multiply. I think it is the 2x^2 - 3x - 20. thank you

Answer 9

^that's right

Answer 10

thanks everone. i have anonther problem like this it is (12-7x)(5+3x).
is this right
12*5+12+3x-7x*5-7x*3x
60+36x-35x-21x^2
60+x-21x^2
?

Answer 11

yes, although you wrote 12 + 3x, but you did calculate it correct as 12 * 3x
And you usually write the result with the highest power first, so the result would be
-21x^2 + x + 60