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OpenStudy (anonymous):
Solve for x
3^x = e^2
13 years ago
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OpenStudy (anonymous):
\[3^{x} = e ^{2}\]
Show work
13 years ago
OpenStudy (lgbasallote):
i would get the square root of both sides first to make e alone...
\[\large \sqrt{3^x} = e\] do you understand that?
13 years ago
OpenStudy (anonymous):
I don't have to use ln?
13 years ago
OpenStudy (lgbasallote):
you will
13 years ago
OpenStudy (lgbasallote):
i'll simplify this into \[\large 3^{x/2} = e\] you understand that algebra right?
13 years ago
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OpenStudy (anonymous):
first of all e=2.71828
so 2.71828^2=3^x
7.38905=3^x
x=1.82048
13 years ago
OpenStudy (anonymous):
Where did you get the 7.389..?
When do I use ln?
13 years ago
OpenStudy (lgbasallote):
\[\large 3^{x/2} = e\] \[\log_e 3 = \frac{x}{2}\] \[\ln 3 = \frac{x}{2}\] \[x = 2\ln 3\] \[x = \ln 3^2\] \[x = \ln 9\]
13 years ago
OpenStudy (anonymous):
Its telling me the answer should be 2/ln 3= 1.820
13 years ago
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OpenStudy (anonymous):
take the natural log to start off with right away.
you'll get
ln3^x = 2
when you have a log raised to a power, you can bring the power down
x * ln3 = 2
get x by itself
x = 2/ln3
ta - daaaaaaaaaaa
13 years ago
OpenStudy (anonymous):
:D lol thanks!
13 years ago
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