Question

Differentiate
f(x) = 30 + 10e^-0.05x

Answer 1

\[f(x) = 30 + 10e ^{-0.05x}\]

Answer 2

well, the derivative of e^ax is just a*e^ax

the derivative of a constant is 0

and the 10 in front of e^x can be pulled out of the derivative, and put back in afterwards.

thus, it'll be -.5e^-.05x

Answer 3

\[f'(x) = 10e ^{^{-0.05x}} + 0\]
Do I multiply 10 by 0.05?
\[f'(x) = -.5e ^{-0.05x} \]

Answer 4

yep yep that is the right process

you can take the derivative of each term (constant and e^x), the derivative of e^x is pretty much like the power rule, a*e^ax, if a = 1 then e^x = e^x.

Answer 5

thank you!! :)