Given 28.2 grams of an unknown substance, if the substance absorbs 2165 joules of energy and the temperature increases by 35 Kelvin, what is the specific heat of the substance?

Question

anonymous · Answer

Specific heat of a substance is the amount of heat required to raise the temperature of 1 g of a substance by 1K.

anonymous · Answer

c=q/mdeltaT

anonymous · Answer

so, 2165 J is required for raising the temp. by 35K right? then how much is required for raising the temperature by 1K?

anonymous · Answer

http://openstudy.com/study#/updates/4fb7af56e4b05565342d231e

anonymous · Answer

DH = m cp DT so -> cp = DH/m DT = 2165J / 35 K * 28,2g = 2,2 J g-1K-1

anonymous · Answer

@alexalva93  this helps u

anonymous · Answer

Yes Thanks

anonymous · Answer

@alexalva93  u have nt given medal to @Kryten  or @open_study1