Question

f(x)=x^(1/x)
f'(x) = ?
and how?

Answer 1

well take natural log on both sides
we have ln(fx) = (ln x)/x
now differentiate both sides :
(f'x)/(fx) = -(ln x)/x^2 + 1/x^2
we have fx =x^(1/x)
just solve for f'x ..
was i clear enough ?

Answer 2

thanks btw :)

Answer 3

glad to help ^_^

Answer 4

is it [1-lnx] x^((1/x) -2) ?

Answer 5

didnt get what you're asking ?

Answer 6

ohh..you're asking the final ans?

Answer 7

am really sorry,,too lazy to do that.. :P
but if do it well enough,,should be correct :)

Answer 8

i need to find global maxima of fx that's why i was asking it.. =D

Answer 9

just put your f'x =0
and to make sure if its maxima,,check for f''x (gets bit complicated though)

Answer 10

ya i got it its maxima is at x=e try making its graph.. it was fun. thanks =)

Answer 11

glad to help ^_^