Put your answer in lowest terms, in descending powers of a, and place variables alphabetically: a^2-b^2/a^3-b^3=________
a^2 - b^2 =(a+b)(a-b) a^3 - b^3 = (a-b)(a^2 -ab + b^2) just make these substituions and you should get your ans
What do you mean by make these substitutions, do I factorize them and then put it in alphatebical order?
these are already factorised.. just put the RHS of a^2-b^2 in numerator and RHS of a^3 -b^3 in denominator,,cancel out same terms and voila! you get your ans!
what does RHS stad for?
*stand
right hand side.. like in x=4 x is LHS (left hand side) and 4 is RHS(right hand side)
Okay and do you know how I can factor x^2+4xy+4y^2?
can you tell me the expansion of (x+y)^2 ?
x^2+2xy+y^2 ?
yep..and what if i ask (x + 2y)^2 ?
x^2+4xy+2y^2 ?
bingo!! isnt that what you were looking for?
ohh..not 2y^2,,its (2y)^2 i.e 4y^2
Yeah, that is where I get lost..
so,,you get your answers right?
Could you factorize all the trinomial please? Because if I do it with the 2y all to the ^2 it does not give me a right answer, it just gets all messed up
hmmn,,you want only the answer right?
no, Im saying could you explainn the whole thing
alright,,leme try in your first ques we have (a+b)(a-b)/ (a-b)(a^2 -ab +b^2) => (a+b)/(a^2 - ab +b^2) --> which i guess should be the ans [note that (a-b) is common and gets cancelled out] in the second ques..you yourself reached the ans.. it is (x+2y)^2..
Okay, thank you
hmm..glad to have helped ^_^
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