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If tan x ̊= 3/y and cos x ̊=y/z, what is the value of sin x°?
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does that ugly picture help?
the picture shows an angle \(x\) with \(\tan(x)=\frac{3}{y}\) and also \(\cos(x)=\frac{y}{z}\)
use the ratio \(\sin(x)=\frac{\text{opposite}}{\text{hypotenuse}}\) to get your answer
an alternative approach is to note that:\[\tan(x)=\frac{\sin(x)}{\cos(x)}\]therefore:\[\sin(x)=\cos(x)\times\tan(x)\]
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that would certainly be snappier, wouldn't it?
So is z/3 the answer?
you have it upside down
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