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OpenStudy (anonymous):
Expand: (2s-3t)^5
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OpenStudy (saifoo.khan):
binomial?
OpenStudy (anonymous):
Yea.
OpenStudy (saifoo.khan):
dont u know the formula ?
OpenStudy (anonymous):
Wasnt given one.
OpenStudy (saifoo.khan):
FAIL.
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OpenStudy (anonymous):
How am I a fail? I wasnt given one or taught one..
OpenStudy (saifoo.khan):
Then how they taught you Binomial expansion?
OpenStudy (anonymous):
32 s^5-240 s^4 t+720 s^3 t^2-1080 s^2 t^3+810 s t^4-243 t^5
OpenStudy (anonymous):
No, teacher gave me a page of them to do.
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OpenStudy (anonymous):
Thank you, Eyad.
OpenStudy (anonymous):
yw :)
OpenStudy (saifoo.khan):
Direct answers! D:
OpenStudy (anonymous):
Under your explanation and your rule :P
OpenStudy (anonymous):
You werent helping much, lol. Just telling me that I was a fail. @saifoo.khan
Yea, teamwork :)@Eyad
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sam (.sam.):
(2s-3t)^5
Just expand
\[^5C_0(-3t)^0(2s)^5=\]
\[^5C_1(-3t)^1(2s)^4=\]
\[^5C_2(-3t)^2(2s)^3=\]
\[^5C_3(-3t)^3(2s)^2=\]
\[^5C_4(-3t)^4(2s)^1=\]
\[^5C_5(-3t)^5(2s)^0=\]
OpenStudy (anonymous):
And that will be my written answer? Or will I have to expand it further?
sam (.sam.):
(p+q)^5
no, you have to use the formula \[^nC_r(q)^r(p)^{n-r}\]
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