Question

Consider the Quadratic function f(x)=−x2+10x−16.
what it's vertex?
x-intercepts?
y-intercepts?

Answer 1

vertex always has first coordinate \(-\frac{b}{2a}\)

Answer 2

in your case you get \(-\frac{10}{2\times(-1)}=5\)
second coordinate is what you get when you replace \(x\) by 5

Answer 3

so x=5 and y=24 ?

Answer 4

x=5 and y=9 !!

Answer 5

\[-5^2+10\times 5-16=-25+50-16=25-16=9\]

Answer 6

so vertex is \((5,9)\)

Answer 7

x-intercepts?

Answer 8

set
\[-x^2+10x-16=0\] and solve for \(x\)
may be easier to solve
\[x^2-10x+16=0\]

Answer 9

try factoring, because this one factors

Answer 10

ok wbu y-intercept?

Answer 11

?