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i need help with this chain rule question [x^3 + (2x-1)^3]^3 how do i solve this?
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power rule it first 3[x^3 + (2x-1)^3]^2 now take the derivative of x^3 + (2x - 1)^3 what is it?
3x^2 + 3(2x-1)^2 x 2
good so combine all of the info
how though? thats where i get confused
\[\large 3[x^3 + (2x - 1)^3]^2 [3x^2 + 6(2x-1)^2]\]
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notice how in the right side i just multiplied 3 and 2 to get 6
yes
so you're okay now?
okay so power rule it and then diffrentiate the inner bit and combine all togetther! Thank you!
yep...you can simplify this by algebra actually ...
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i mean simplify further..by factoring out 3
yess got it! thanks!
okay then ^_^
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