Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Sheila plans to row across the lake from point A to point B as shown below. To determine how far she will have to row, she has chosen a point C and calculated the labeled data. How many miles will she have to row? Round your answer to two decimal places.

OpenStudy (anonymous):

OpenStudy (anonymous):

use the law of cosines.. do you know it?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

This is the law of cosines: \[\large c^2=a^2+b^2-2abcos(C) \] where a and b are the given sdes and angle C is the included angle....

OpenStudy (anonymous):

but how can i use that when i dont know a and b?

OpenStudy (anonymous):

you have two given sides...

OpenStudy (anonymous):

okay so so far i have =243.36 for both the sides

OpenStudy (anonymous):

both sides?

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

\[\large c^2 = 12.3^2+15.6^2-2(12.3)(15.6)cos(56.7) \]

OpenStudy (anonymous):

i got \[\large c^2=183.957 \]

OpenStudy (anonymous):

i got a big number :/

OpenStudy (anonymous):

so rounded to 2 decimal places is

OpenStudy (anonymous):

wait... this is c^2 NOT c....

OpenStudy (anonymous):

you want c....

OpenStudy (anonymous):

so c is 91.9785

OpenStudy (anonymous):

no... take the square root...

OpenStudy (anonymous):

so 13.563074...

OpenStudy (anonymous):

that's it... btw... how are you supposed to do these problems if you're not familiar with the law of cosines?

OpenStudy (anonymous):

so rounded to 2 decimal places is what? no i do im just tired and have a lot of work

OpenStudy (anonymous):

ok...

OpenStudy (anonymous):

so rounded to two decimal places is 13.56?

OpenStudy (anonymous):

@dpaInc

OpenStudy (anonymous):

yes...:)

OpenStudy (anonymous):

thank you! :)

OpenStudy (anonymous):

yw...:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!