Solve: 4p^2+4p+1=0 Solve for both "P's"
@vanes5623 do you know the expansion of this \[(a+b)^2?\]
what do you mean?
\[(a+b)^2=a^2+b^2+2ab\] do you know this?
i think so
4p^2+4p+1=0 Can you simplify the left side, use the hint, I gave you!!
I can't. I'm so confusedd!
What's the expansion of this? \[(2p+1)^2??\]
I dont know..?
Use the formula \[(a+b)^2=a^2+2ab+b^2\] a=2p and b=1 here
I'm sorrry. I can't do it.
Try once, simplify just the right side \[(2p+1)^2=(2p)^2+2\times (2p) \times (1)+1^2\]
I can't. I'm so confusedd!
What's the square of 2p?
im only a freshman in high school. I don't understand this
can i just have the answer.. please
lol okay for starters on OS never just ask for an answer. That annoys long-time users lol And Algebra I sucked so I feel your pain either way p = -1/2 @ash2326 explained it perfectly to you, I figured it out by working out his examples! haha It's kind of hard to keep up but if you pay close attention it's not so bad :3
Don't forget to give Ash a medal for taking the time to help you :)
Join our real-time social learning platform and learn together with your friends!