Question

Can anyone help me differentiate this: 1/3 x^3 +3/2x^2-7

Answer 1

Hint: \[\frac{d}{dx} x^n=nx^{n-1}\]\[\frac{d}{dx} C\cdot f(x) = C\cdot \frac{d}{dx}f(x)\]\[\frac{d}{dx} \left( f(x) + g(x) \right) = \frac{d}{dx} f(x) + \frac{d}{dx} g(x)\]

Answer 2

is that

( 1/(3x^(3)) ) + ( 3/(2x^(2)-7) )

Answer 3

well they are added s just differentiate

( 1/(3x^(3)) )

and

( 3/(2x^(2)-7) )

then add the two derivatives

1/(3x^(3)) = 3x^(-3)
and
( 3/(2x^(2)-7) )= 3(2x^(2)-7)^(-1)

thus we have

3x^(-3) + 3(2x^(2)-7)^(-1)

can you solve this?

Answer 4

for the first one use the rule yakeyglee posted

for the second one use chain rule

Answer 5

Note I simply used this rule to put it in a form that is easier to deal with

Answer 6

ok I get it

Answer 7

thanks everyone