Question

Give the foci of x^2/9+y^2/4=1
(sq.rt of____,____),(-sq rt. of___,____)

Answer 1

the foci is obtained using the value of c in c^2 = a^2 - b^2, where a=3, b=2. once you find the value of c, move c units up and down from the center to get your foci.

Answer 2

can you give the value of c?

Answer 3

c= sq. root of 13

Answer 4

subtract.. don't add...

Answer 5

c^2 = a^2 - b^2 = 3^2 - 2^2 = 9 - 4 = 5
so c = sqrt5

Answer 6

plus/minus sqrt5

Answer 7

also... sorry 'bout the mistake up there... the center is (0, 0) and you go left/right of the center, NOT up/down of the center.

Answer 8

okay thanks, is it the same for a hyperbola? Do I add or subtract?