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Chemistry 17 Online
OpenStudy (maheshmeghwal9):

I wanna ask that how can the following is true?

OpenStudy (maheshmeghwal9):

why is it true "the last equation"?

OpenStudy (maheshmeghwal9):

i mean "3 x a" shouldn't be equal to "1 x a".

OpenStudy (maheshmeghwal9):

@apoorvk Plz help:)

OpenStudy (maheshmeghwal9):

@Zarkon plz help:

OpenStudy (apoorvk):

Yeah, it seems like a typing error. Should read actually: "1 x 'Moles of Mg' in Mg3N2 = 3 x 'Moles of Mg' in Mg(OH)2" since, 1x3 = 3 x 1

OpenStudy (maheshmeghwal9):

but this is not a typo. i have googled it.

OpenStudy (maheshmeghwal9):

the attachment is 100% correct:)

OpenStudy (anonymous):

Yes I agree with @apoorvk, balance your equation and you will have \[1 mole sof Mg_3 N_2=3Moles Mg(OH)_2\]

OpenStudy (apoorvk):

What is the source of this attachment? And, what do you mean 'googled it'? reverse image search?

OpenStudy (apoorvk):

I can only say it's wrong, atleast in this world. -_- Or may be, I am really ignorant regarding this. Perhaps, @Limitless may help.

OpenStudy (anonymous):

It would seem that Apoorvk is right. His argument hinges on: \[\text{moles}(Mg_{j})=\text{moles}(jMg_{1})\] He is also assuming: \[\text{moles}(Mg_{j})=j\] and \[\text{moles}(jMg_{1})=j \cdot\text{moles}(Mg_{1})=j\] If the \(\text{mole}(x)\) function behaves that way, he is right. I would think it does, but I can't vividly recall chemistry.

OpenStudy (paxpolaris):

the picture is true..... it says: \( 3 \times\) the number of moles of \(Mg_3N_2\) used= \( 1 \times\) the number of moles of \(Mg(OH)_2\) produced

OpenStudy (apoorvk):

"3× the number of moles of Mg3N2 used= 1× the number of moles of Mg(OH)2 produced" I don't really think this is^ correct either, @PaxPolaris

OpenStudy (paxpolaris):

if you have 2 mol \(Mg_3N_2\) ..... and 6mol \(Mg(OH)_2\) \[3 \times 2 =1 \times 6 \]

OpenStudy (paxpolaris):

this is true because the number of moles Mg atoms on both sides has to be the same there are 3 times as many Mg atoms as \(Mg_3N_2\) molecules on the left ................ 1 times as many Mg atoms as \(Mg(OH)_2\) molecules on the right

OpenStudy (anonymous):

i think this only serves to give you Mg ratio where it is true that: \[_{Mg(OH)2}^{Mg3N2} = _{1}^{3} \rightarrow Mg3N2 = 3 Mg(OH)2\]

OpenStudy (apoorvk):

@paxpolaris - what you are doing is just adjusting something to justify the statement. Make no sense to me. @maheshmeghwal9 - do think yourself about this.

OpenStudy (maheshmeghwal9):

ya I have got it. thanx to all for help:) & one more thing @PaxPolaris is correct:)

OpenStudy (apoorvk):

aahh... now i get it. Hmm, though must admit the statements are very poor.

OpenStudy (anonymous):

@maheshmeghwal9 i think @PaxPolaris is correct

OpenStudy (maheshmeghwal9):

ya but i wanna know how can it be in the last statement 3 x3 =1 x1

OpenStudy (anonymous):

Basically. . In POAC, we don't really balance any equation because we wan't the reactant side ka moles and the product side ma moles to be EQUAL! That's what all POAC is about. For eg in ca + o gives cao. Now in Ca has equal number of moles as in Ca in CaO. Basically, the reactant and prodduct side must have equal moles. So now by subsituiting their weight and molecular weight and atomic weight, or whatever, we can find the required thing

OpenStudy (anonymous):

http://in.answers.yahoo.com/question/index?qid=20100512080359AAbrpB3 these may help u if u have doubts then inform me!

OpenStudy (apoorvk):

It's the no. of moles used vs the no. of moles produced actually. so that's correct

OpenStudy (maheshmeghwal9):

k! thanx:)

OpenStudy (maheshmeghwal9):

to both.

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