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Derivative of 2^(-1/x)
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\( \color{Black}{\Rightarrow x^n \Rightarrow nx^{n - 1} }\)
This is how you find the derivative ^
that only works when x is base and exponent is constant
derivative of \(a^x = a^x\ln a\) if i remember right
how might I end up with the answer 2^(-1/x) ln2/x^2
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like i said derivative of a^x = a^x ln a here your a is 2 so it's 2^(-1/x) ln 2 but wait! you have to take the derivative of -1/x as well
derivative of -1/x = 1/x^2
so combining all of that you will get 2^(-1/x) ln 2 / x^2 got it?
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