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Mathematics 15 Online
OpenStudy (yash2651995):

y=1/log(cos x) dy/dx=? answer in book is= tan x/[log(cos x)]^2 i took 1= ln e and then lnA/lnB=ln (A-B) then chain rule i cant convert my anwer to the one given, am i right? or i made a mistake?

OpenStudy (anonymous):

What's the base of your log 10?

OpenStudy (yash2651995):

nah.. e ie Euler's number

OpenStudy (anonymous):

why don't you use the change of base formula?

OpenStudy (yash2651995):

it is log to base e every where.. even in question it is log to base e

OpenStudy (anonymous):

That is fine but \[\log_a x= lnx/lna\]

OpenStudy (anonymous):

SO that you have \[\ln(cosx)/lne\] and \[lne\] is just 1

OpenStudy (anonymous):

\[y= 1/\ln(cosx)\]

OpenStudy (anonymous):

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