Question

\[\left| x+2 \right| + x + \left| x-1 \right|-3=0\]

Answer 1

consider intervals , for x<-2 we have

(-x-2) + x +(1-x) - 3 =0

for -2<x<1 we have

x + 2 + x + (1-x) -3 = 0

for 1>x we have

x+2 + x + x -1 -3 = 0

Answer 2

so wat the interval period....

Answer 3

basically consider each interval where the modulus functions change, and solve each equation

for x<-2 we have

(-x-2) + x +(1-x) - 3 =0

-x -2 + x + 1 -x -3 = 0

-x - 4 = 0

x = -4

now check if this works,

-4<-2

so it is valid

next you need to consider -2<x<1

Answer 4

ok let me try and will inform u!!

Answer 5

:D

Answer 6

thxx lol @eigenschmeigen i understod the method!

Answer 7

@eigenschmeigen help http://openstudy.com/study?signup#/updates/4fd0936ee4b0e04663181e2a