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differentiate y=lnx/sqrtx
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take your pick: quotient rule or product rule
product rule
good choice rewrite this as\[y=\ln x(x^{-1/2})\]now if you know the product rule this should not be so bad
is it 1/x times -1/2x^3/2
no, the product rule is\[(uv)'=u'v+v'u\]what are u and v in your case?
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sorry long time since i did maths - trying hard to bring it back
i thought if I worked out y=ln2x and y=1/sqrtx i could then multiply them together
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