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Mathematics 14 Online
OpenStudy (anonymous):

differentiate y=lnx/sqrtx

OpenStudy (turingtest):

take your pick: quotient rule or product rule

OpenStudy (anonymous):

product rule

OpenStudy (turingtest):

good choice rewrite this as\[y=\ln x(x^{-1/2})\]now if you know the product rule this should not be so bad

OpenStudy (anonymous):

is it 1/x times -1/2x^3/2

OpenStudy (turingtest):

no, the product rule is\[(uv)'=u'v+v'u\]what are u and v in your case?

OpenStudy (anonymous):

sorry long time since i did maths - trying hard to bring it back

OpenStudy (anonymous):

i thought if I worked out y=ln2x and y=1/sqrtx i could then multiply them together

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