PLEASE HELPP MEEE!
Find the x-intercepts of the graph of each function: y=x^2+2x
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OpenStudy (accessdenied):
Do you understand what the term "x-intercept" means, like in terms of the graph?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Do i factor the x^2 + 2x?
OpenStudy (accessdenied):
Once we have the equation (y=0 for x-intercepts)
x^2 + 2x = 0
Yes, we can factor here to solve for the x-values.
OpenStudy (anonymous):
ok let me work it out
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OpenStudy (anonymous):
x(x+2)
OpenStudy (accessdenied):
Yep, that's correct.
Now, we just equate each factor to 0 to solve (If ab = 0,. then a= 0 or b= 0)
OpenStudy (anonymous):
y = x^2 + 2x
y = x(x+2)
x = 0
or
x+2 = 0
x = -2
OpenStudy (anonymous):
i got x=0 or x=-2!
OpenStudy (anonymous):
if finding x intercepts , then you make it so that y = 0
and then solve (that's what i did)
y = x^2 + 2x
0 = x^2 + 2x
0 = x(x+2)
and so then you get x = 0 and -2
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OpenStudy (anonymous):
thank you both so much this really helped a lot!
OpenStudy (anonymous):
if you ever have to find y -intercepts, you set X equal to 0 as opposed to Y. no problem (: