Question

can someone integrate 1/4x^2

Answer 1

@Rogue answered this already :O

Answer 2

I asked this question earlier, but made a mistake and wrote differentiate, instead of integrate.

Answer 3

he wrote the integral

Answer 4

How do i go back to my first problem? I didn't see it.

Answer 5

go to your profile (you can bress that bar beside the f button) then questions asked

Answer 6

ok thank you.
can you tell me if my answer is correct? I got -1/16x^2 when finding the integration of 1/(2x)^3

Answer 7

@lgbasallote , how to you "bress" something?

Answer 8

*how do

Answer 9

@lgbasallote. Can you tell me if my answer is correct? I got -1/16x^2 when finding the integration of 1/(2x)^3.

Answer 10

let me think -_-

Answer 11

i'll check by differentiating -1/16x^2 should come out as 1/(2x)^3

\[\frac{d}{dx}(\frac{-x^{-2}}{16}) = \frac{2x^{-3}}{16} = \frac{2}{16x^3} = \frac{1}{8x^3} = \frac{1}{(2x)^3} \checkmark\]

Answer 12

Thank you.