Question

(4x^4-4x^3+5x^2-4x+1)/(2x-1)

Answer 1

is this a remainder problem again?

Answer 2

problley

Answer 3

you can use the same theorem here by rearranging the equation as follows:\[\frac{4x^4-4x^3+5x^2-4x+1}{2x-1}=\frac{4x^4-4x^3+5x^2-4x+1}{2(x-0.5)}\]

Answer 4

so now your f(x) is given by:\[f(x)=\frac{4x^4-4x^3+5x^2-4x+1}{2}\]and the remainder would be calculated by working out f(0.5)

Answer 5

so i divide all that by 2

Answer 6

substitute x=0.5 into f(x) and the resulting value will be your remainder

Answer 7

i dnt get it!!!!

Answer 8

i.e. work this out:\[\frac{4(0.5)^4-4(0.5)^3+5(0.5)^2-4(0.5)+1}{2}\]here I have replaced all occurrences of x in the expression for f(x) by the value 0.5

Answer 9

I would sugest you study this to become more familiar with it: http://www.mathsisfun.com/algebra/polynomials-remainder-factor.html

the remainder theorem is described about a quarter of the way down on that web page.

Answer 10

i still dnt get it

Answer 11

Or just use synthetic division,
(4x^4-4x^3+5x^2-4x+1)/(2x-1)