PLEASE HELP WITH THIS VECTORS PROBLEM! a) Write a vector equation and parametric equations of the line through P(3 , 5) and Q(-4 , 7). b) Write the scalar equation of the line with parametric equations: x=6-7t , y=-2+3t Please show all work, Thanks (:
First work out the vector through those two points P and Q Q(-4, 7) - P(3, 5) vector QP = (3 - (-4) , 5 - 7) = (7, -2) Now that we have a vector we simply write the vector equation the general form of the vector equation is (x,y) = Xo + t(v) (x,y) = (-4,7) + t(7, -2) **** This is the vector equation To obtain parametric equation, you simply break down the above equation for x and y x = -4 + 7t y = 7 -2t
When does part a) end?
that is part A, Im not sure about part B
Oh, so the answer is x = -4 + 7t y = 7 -2t?
@javawarrior ?
yes those are the parametric equations
Thanks :) How do we do part b)?
From my part of the world, the scalar equation is referred to as the general equation. simply take these equations: x=6-7t y=-2+3t and try to eliminate t The general form the equation should be Ax + By = D
How do we eliminate t?
just take a multiple of one equation and minus the other to get rid of t
Can you take me through it?
@javawarrior ?
@lgbasallote can you solve those 2 equations to eliminate T ?
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