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OpenStudy (lgbasallote):
are you familiar with the identity sin(2a) = 2sinacosa?
OpenStudy (lgbasallote):
let's make it prettier
sin(2a) = 2sin(a)cos(a)
OpenStudy (anonymous):
Im not familiar with it.
OpenStudy (lgbasallote):
well your teacher should teach that to you before giving these exercises lol =)) anyway keep that in mind coz im going to use that here and it is used a lot in later maths
sin(2a) = 2sin(a)cos(a)
now if i replace a by x/5 i will get
sin (2x/5) = 2sin(x/5)cos(x/5)
agree?
OpenStudy (anonymous):
okay yeah
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OpenStudy (lgbasallote):
now if i divide both sides by 2 i will get
\[\large \frac{\sin (\frac{2x}{5})}{2} = \sin (\frac{x}{5}) \cos (\frac{x}{5})\] ^the 2 in the right side got canceled
OpenStudy (lgbasallote):
now what can you conclude?
OpenStudy (anonymous):
That its false?
OpenStudy (lgbasallote):
let me rewrite that...i can express this as \[\frac{1}{2} \sin (\frac{2x}{5}) = \sin (\frac{x}{5}) \cos (\frac{x}{5})\]
OpenStudy (lgbasallote):
isn't \[\frac{a}{2} = \frac{1}{2} a?\]
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OpenStudy (lgbasallote):
now again..is the equation in your question true? or false?