cos(x/5) sin(x/5)=½[sin(2x/5)] true or false?
are you familiar with the identity sin(2a) = 2sinacosa?
let's make it prettier sin(2a) = 2sin(a)cos(a)
Im not familiar with it.
well your teacher should teach that to you before giving these exercises lol =)) anyway keep that in mind coz im going to use that here and it is used a lot in later maths sin(2a) = 2sin(a)cos(a) now if i replace a by x/5 i will get sin (2x/5) = 2sin(x/5)cos(x/5) agree?
okay yeah
now if i divide both sides by 2 i will get \[\large \frac{\sin (\frac{2x}{5})}{2} = \sin (\frac{x}{5}) \cos (\frac{x}{5})\] ^the 2 in the right side got canceled
now what can you conclude?
That its false?
let me rewrite that...i can express this as \[\frac{1}{2} \sin (\frac{2x}{5}) = \sin (\frac{x}{5}) \cos (\frac{x}{5})\]
isn't \[\frac{a}{2} = \frac{1}{2} a?\]
now again..is the equation in your question true? or false?
The last one makes sense. True.
there you go :D
thanks (:
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