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Simplifying the following: \[\frac{(n-2)!(n+1)!}{(n!)^2}\] The way I did it was expanding \((n-2)!\): \[\frac{(n-2)(n-1)(n)!(n+1)!}{(n!)^2}\] Then I cancelled out the n! to give: \[\frac{(n-2)(n-1)(n+1)!}{n!}\] I tried to continue this by expanding the (n+1)!, then cancelling out the bottom 'n' to give \[(n-2)(n-1)(n+1)\] But the correct answer is \[\frac{n+1}{n(n-1)}\] I'm assuming I made a mistake somewhere or my methodology is not quite right.
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do you have an answer key to this?
ohhh idid make a mistake
|dw:1339116703913:dw|
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