Question

Find the vertex of the parabola for the equation:

3x2 - 6x - 5

A. (1, -4)
B. (1, -8)
C. (-1, -4)
D. (-1, -8)

Answer 1

3x^2 - 6x - 5
=3(x^2-2x) -5
=3(x^2-2x+1-1)-5
= 3(x-1)^2 -3-5
= 3(x-1)^2 -8

For quadratic equation having the form y=a(x-h)^2 +k
(h,k) are the coordinates of the vertex.

Compare 3(x-1)^2 -8
with a(x-h)^2 +k
Can you get the vertex now?

Answer 2

Yes Thank You

Answer 3

welcome!