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OpenStudy (anonymous):
2x-6 = (x-3)e^sinx
how do you get rid e^sinx? also, what is this type of problem called?
13 years ago
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OpenStudy (anonymous):
2x-6/x-3=e^sinx
2(x-3)/x-3=e^sinx
2=e^sinx
Ln2=sinx
x=arcsin (Ln2)
13 years ago
OpenStudy (anonymous):
it's an equation
13 years ago
OpenStudy (anonymous):
what type of equation? with the base e^sinx
13 years ago
OpenStudy (anonymous):
thank you!
13 years ago
OpenStudy (anonymous):
not any speial type. You wellcome
13 years ago
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OpenStudy (lgbasallote):
2x-6 = (x-3)e^sinx
2x - 6 = xe^sinx - 3e^sinx
3e^sinx - 6 = xe^sinx - 2x
3e^sinx - 6 = x(e^sinx -2)
x = \(\frac{3e^{\sin x} - 6}{e^{\sin x} -2}\)
that's how you get rid of it @camialtrs93 take note of the method as it is used a lot
13 years ago
OpenStudy (anonymous):
and how you solve for x now?
13 years ago
OpenStudy (anonymous):
@lgbasallote
13 years ago
OpenStudy (lgbasallote):
\[\large x = \frac{3e^{\sin x} - 6}{e^{\sin x} -2}\] \[x = \frac{3\cancel{(e^{\sin x} - 2)}}{\cancel{e^{\sin x} - 2}}\] @myko
13 years ago
OpenStudy (anonymous):
:)
13 years ago
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OpenStudy (lgbasallote):
the asker wanted the e^sinx gone lol
13 years ago
OpenStudy (anonymous):
oh alright, thanks @lgbasallote!
13 years ago
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