One number is 7 more than the other and its square is 77 more than the square of the smaller number. What are the numbers?

Question

anonymous · Answer

express the numbers in terms of x; 
$$x.... and..... 7 +x$$

jiteshmeghwal9 · Answer

plz, give me the whole ans. step by step:)

anonymous · Answer

then: as the square of the smaller number is 77 less than the square of the bigger number we have this equation:

$$(x +7) ^2 = (x^2) + 77$$

jiteshmeghwal9 · Answer

k!

anonymous · Answer

next expand: (x + 7)^2

anonymous · Answer

to give:$$x^2 + 2(7x) + 49$$

anonymous · Answer

then solve the equation, can you do it from here?

jiteshmeghwal9 · Answer

I have a little confusion here:(

jiteshmeghwal9 · Answer

where u expanded @bbsmilieface

anonymous · Answer

Let a and b be the largest and smallest numbers respectively.  Solve the following for a and b:$$\left\{a=b+7,a^2=b^2+77\right\} $$$$\{a=9,b=2\} $$

jiteshmeghwal9 · Answer

mean of expand?

jiteshmeghwal9 · Answer

I can solve the eq. but didn't understand expand

anonymous · Answer

expansion of  (x + 7) (x + 7):|dw:1339169004095:dw| where the arrows are timesing