If two balls are drawn without replacement from a box containing 3 red balls, 2 black balls, and one green, what is the probability of getting 2 red balls?

Question

parthkohli · Answer

$ \color{Black}{\Rightarrow \Large {3 \over 6} \times {2 \over 5}}$

parthkohli · Answer

Note how I decreased one from both numerator and denominator because we're not replacing.

anonymous · Answer

ok..so I cross multiply?

parthkohli · Answer

Something is getting cancelled :)

parthkohli · Answer

$ \color{Black}{\Rightarrow \Large {1 \over 2} \times {2 \over 5} }$

anonymous · Answer

The 2/5 right?

parthkohli · Answer

Nu uh

parthkohli · Answer

I simplified the 3/6 to 1/2

anonymous · Answer

oh okay..

anonymous · Answer

so whats the answer..?

parthkohli · Answer

$ \color{Black}{\Rightarrow \large {2 \over 10} = ...? }$

anonymous · Answer

Ummmm...and now I have 1/5 is that right?