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Explain how to find the solution to this equation: 64^(x – 3) = 4^(2x)
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\[64^{x-3}=4^{2x}=>4^{3(x-3)}=4^{2x}\] So \[3(x-3)=2x=>x=9. Ans........\]
gt it?
Um not 100%. Can you explain please using sentences what you did there...
ya ! u have right to know this:) NOTE: - When 2 exponents with same base related by the sign of equality, are anywhere; just do this: - that exponents will be equal.
thanks :)
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yw:) so is it 100%
i mean did u gt it 200%?
yes I got it! I was solving these fine but idk why I got stumped on that one
don't worry about maths when u have OS^_^
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