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If sin\(\theta\)+cosec\(\theta\)=2 then \(sin^n\theta +cosec^n\theta\)=2. How do we get this relation?
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Hi ujjwal :) I think we have need to use mathematical induction.
Ok but that would be proving the relation rather than deriving it.
To prove it by mathematical induction, do we need to put an arbitrary value for \(\theta\)?
Yes. I think I can prove it but it will use some mind lol :D
try this
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No. not for \[\theta \] for whole sine. Because sine also exist in cosec.
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