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Mathematics 13 Online
OpenStudy (anonymous):

How would simplify: n!/((n+1)!+(n-1)!)

OpenStudy (anonymous):

Is it: \[\frac{n!}{(n+1)!+(n-1)!} \]?

OpenStudy (anonymous):

Here's a hint. (n+1)! means the product of all numbers from n + 1 to 1.

OpenStudy (anonymous):

Yes, do you mean (n+1)!= (n+1)n(n-1)...1?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Also, \(n!=n*(n-1)*(n-2)*...\)

OpenStudy (anonymous):

oh, and i should take out the common (n-1) factor from denominator?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Well actually the common factor is (n-1)!

OpenStudy (anonymous):

ah ok. i got it. Thanks!

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