if two zeroes of the poly.x^4-7x*3+17x^2-17x+6 are 3 and 1.find the other zeroes of the poly.
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OpenStudy (anonymous):
@apoorvk
OpenStudy (anonymous):
@lgbasallote
OpenStudy (lgbasallote):
did you know that since 3 and 1 are zero then:
x = 3 and x = 1
therefore (x-3) and (x-1) are factors of the polynomial
OpenStudy (anonymous):
k dennnn
OpenStudy (lgbasallote):
so (x-3)(x-1) = x^2 - x - 3x + 3 = x^2 - 4x = 3
now divide the polynomial given with this
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OpenStudy (anonymous):
frm where u gt x^2 - x - 3x + 3
OpenStudy (apoorvk):
If the zeroes of this polynomial are 3 and 1, that means (x-3) and (x-1) are factors of this polynomial.
Divide the polynomial by any of the factors, and obtain a quotient in terms of 'x'. This quotient will be a cubic.
Then divide this quotient again, this time by the other factor. You 'll get a quadratic.
Factorise this quadratic and get your roots!
OpenStudy (lgbasallote):
FOIL (x-3)(x-1)
OpenStudy (apoorvk):
or as @lgbasallote says, divide it by (x-1)(x-3) just once, and get the quadratic.
OpenStudy (anonymous):
so x=3 and x=1
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OpenStudy (anonymous):
????????????????????????/
OpenStudy (anonymous):
ma bulb is fused it is nt glowing wht to do
OpenStudy (lgbasallote):
where did you get lost??
OpenStudy (anonymous):
c i gt (x-3) and (x-1)
den wht did u do? @lgbasallote
OpenStudy (lgbasallote):
(x-3) and (x-1) are factors of the polynomial in the question..do you get that?
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