Find the missing measures for a right circular cone. r = 6 l = 10 h = http://media01.switchedononline.com/a_matgeo_2010/7/mat1007l16p01_05.jpg
the only part i need help with is finding out what h =
i understand the rest of the process
Do they give you the surface area or volume? How did you get the other parts?
How did you find the other parts?
LA = PIE(r)(l) TA = PIE (R)(L) + pieRsquared
v = 1/3 pie (r squared)h
la = 60pie ta = 96pie i need to know how to figure out the h so I can answer the rest of the problem
Alright. Work backwards. 60π = πrl 96π = πr^2 + πrl 96π = πr^2 + 60π 36π = πr^2 36 = r^2 r = 6 l = 10 Did they give you the volume?
no i have to figure it out but i need what h is
Actually, you don't need it. You have to imagine this.The radius, the height and the slant height form a right triangle.|dw:1339269135774:dw|
okay so this is a 30 60 90 triangle right
No. It's just a right triangle. Use Pythagorean Theorem. h^2 + 6^2 = 10^2 h^2 + 36 = 100 h^2 = 64 h = ?
8
There you go :)
This is something you're often going to have to do. Remember, you can only do this if it's a RIGHT circular cone.
okay thanks
|dw:1339269350822:dw|
You're welcome :)
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