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OpenStudy (anonymous):
hello...:)
OpenStudy (anonymous):
hello!
OpenStudy (anonymous):
ok summer, you'll need to solve 10=logx
OpenStudy (apoorvk):
Hello too! :D
OpenStudy (anonymous):
hello to everyone lol and yes i need help!
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OpenStudy (anonymous):
can you write that out in it's equaivalent exponential form?
OpenStudy (anonymous):
i have the answer but i need to know how to get it?
OpenStudy (anonymous):
use this...\(\large log_bM=n \Rightarrow b^n=M \)
OpenStudy (anonymous):
answer- x = 1
OpenStudy (anonymous):
ya, all you need to do is write the log equation, \(\large 10=logx\rightarrow 10^{10}=x \)
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OpenStudy (anonymous):
wait... how can x=1?
OpenStudy (anonymous):
idk !
OpenStudy (anonymous):
is y=0 or y=10?
if y=0 then x=1
OpenStudy (anonymous):
i think it is y=0?
OpenStudy (anonymous):
that's the only way x=1 because then you'll have \(\large 10^0=1 \)
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OpenStudy (anonymous):
oh? i did not know that!lol
OpenStudy (anonymous):
could be a misprint on your book?
or if the question is written correctly, then x= \(\large10^{10} \)
OpenStudy (anonymous):
ok so what would it be? i am really confused lol sorry i am not that great at math!
OpenStudy (anonymous):
it depends on what question were talking about...
if the question is \(\large 0=logx \) then x=1,
but if the question is \(\large 10=logx \) then \(\large x=10^{10} \)
OpenStudy (anonymous):
as stated originally, it would be that second one.
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OpenStudy (anonymous):
its the first one!
OpenStudy (anonymous):
so y=0 then? and that implies 0=logx ???
OpenStudy (anonymous):
ya?
OpenStudy (anonymous):
ok....
so it is a misprint...y=0 will give you the equation:
\[\large 0=logx \rightarrow 10^0=x\rightarrow x=1 \]
OpenStudy (anonymous):
ok that makes more sence! thanks so so so so much!!!
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